If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
0 = x*((x^2-4)/2) // - x*((x^2-4)/2)
0-(x*((x^2-4)/2)) = 0
-(x*((x^2-4)/2)) = 0
(-1*x*(x^2-4))/2 = 0
( -1 )
-1 = 0
x belongs to the empty set
( x )
x = 0
( x^2-4 )
1*x^2 = 4 // : 1
x^2 = 4
x^2 = 4 // ^ 1/2
abs(x) = 2
x = 2 or x = -2
x in { 0, 2, -2 }
| (5pq)(qr)(PR)= | | 15-8m=-74 | | -8x+3x=35 | | 8y-3/2y | | Bx=7 | | 4x^2+4=200 | | -2(2-7a)=94 | | 3b+6=21 | | 3-2(2x+6)=4 | | a=v_1-v_0/t | | 12(112)= | | -(b-2)=-6 | | -2+4a=-5(6a-6)+2 | | 5t+16=6-5r | | 3x-6x-7=-3x+4-7 | | 5.2Q-4.6-7.1Q=.9Q-4.6 | | 9(x+2)-1=4x+5(3+x) | | 5.2Q-4.6-7.1Q=.9-4.6 | | 6t^2+8=13 | | -98=4+6(-4x+3) | | 9(38)= | | 3/4(4/5x-2) | | a^2*b=c | | cos(x)=0.3*x | | -4+5p=41 | | 7+4n=79 | | -12-x=8x-7x | | n^2=7n+8 | | 14(1002)= | | 4m-17=32 | | 2(7x+1)=24x+2 | | 7/2(4)-1 |